Statistics
Class X Statistics EXERCISE : 14.4
Question 1:- The following distribution gives the daily income of 50 workers of a factory.
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
Solution: We have the cumulative frequency distribution as:
Now, we plot the points corresponding to the ordered pairs (120, 12), (140, 26), (160, 34), (180, 40) and (200, 50) on a graph paper and join them by a free hand smooth curve as shown below:
The curve so obtained is called the less than ogive.
Statistics EXERCISE : 14.4
Question 2:- During the medical check-up of 35 students of a class, their wrights were recorded as follows:
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph and verify the result by using the formula.
Solution: Here, the values 38, 40, 42, 44, 46, 48, 50 and 52 are the upper limits of the respective class-intervals.
We plot the points (ordered pairs) (38, 0), (40, 3), (42, 5), (44, 9), (46, 14), (48, 28), (50, 32) and (52, 35) on a graph paper and join them by a free hand smooth curve.
The curve so obtained is the less than type ogive.
From the point (i.e., from 17.5) we draw a line parallel to the x-axis which cuts the curve at P. From this point (i.e., from P), draw a perpendicular to the x-axis, meeting the x-axis at
The point Q represents the median of the data which is 47.5.
Verfication
To verify the result using the formula, let us make the following table in order to find median using the formula:
Here, 
Since, the observation lies in the class 46 – 48
The median class is 46 – 48 such that l = 46, h = 2, f = 14, cf = 14
Median = 
= 46.5
Thus, the median = 46.5 kg is approximately verified.
Question 3:- The following table gives production yield per hectare of wheat of 100 farms of a village.
Change the distribution to a more than type distribution, and draw its ogive.
Now, we plot the points (50, 100), (55, 98), (60, 90), (65, 78), (70, 54) and (75, 16) and join the point with a free hand curve.
